No special Example 4: Electric field of a charged infinitely long rod. 1: 58. Yasar, O.; Ulusan, H.; Zorlu, O.; Sardan-Sukas, O.; Kulah, H. Optimization of AA-Battery Sized Electromagnetic Energy Harvesters: Reducing the Resonance Frequency Using a Non-Magnetic Inertial Mass. Feature In Proceedings of the International Conference on Electrical Computer, Communications and Mechatronics Engineering, ICECCME 2021, Mauritius, 78 October 2021; pp. { "00:_Front_Matter" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.
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Since the gap containing the resistor is infinitesimally small, \[V_T = \oint_{\mathcal C} \left[ {\bf v} \times {\bf B} \right] \cdot d{\bf l} \nonumber \], where \(\mathcal{C}\) is the perimeter formed by the loop, beginning at the \(-\) terminal of \(V_T\) and returning to the \(+\) terminal of \(V_T\). By choosing a clockwise to traverse the circuit, we have expressed the associated loop equation as minus i times R minus L times di over dt is equal to 0. The period of circular motion for a charged particle moving in a magnetic field perpendicular to the plane of motion is T = 2m qB. OpenStax College, Maxwellu2019s Equations: Electromagnetic Waves Predicted and Observed. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. ; methodology, T.T. Therefore it will try to generate a current in opposite direction to the direction of flow of this original current. In other words, no additional energy is required to maintain the field, once the steady-state has reached. The result is, \[\int \int_{S u r f a c e}(\vec{A} \times \vec{H}) \cdot d \vec{S}=\int \int \int_{V o l u m e} d \tau\left(\vec{H} \cdot \vec{B}-\vec{J}_{f} \cdot \vec{A}\right), \label{5.43}\]. Salauddin, M.; Halim, M.A. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. 0 Figure \(\PageIndex{1}\) shows a simple scenario that illustrates this concept. In case of an airgap in the core, airgap reluctance being far larger than that of the core, portion of the field energy would reside in the airgap. Maxwell predicted that electric and magnetic forces are linked. ; Thein, C.K. B Some of that energy is dissipated per unit time through the resistor. Only if the magnetic flux changes with time will we observe a current. U = um(V) = (0nI)2 20 (Al) = 1 2(0n2Al)I2. Toluwaloju, T.I. We have defined the concept of energy density earlier, and here also we can define the energy density associated with the magnetic field, the energy density. It should be noted that the total stored energy in the magnetic field depends upon the final or steady-state value of the current and is independent of the manner in which the current has increase or time it has taken to grow. and where \(\mathcal{S}\) is the surface through which the flux is calculated. Apparatus Used by Hertz: The apparatus used by Hertz in 1887 to generate and detect electromagnetic waves. Terms representing these two forces are present along the main diagonal where they act on differential area elements normal to the corresponding axis. This change in potential energy may give rise to an electrical potential difference (i.e., a voltage), as we shall now demonstrate. interesting to readers, or important in the respective research area. The line integral of the vector potential around a closed circuit is equal to the magnetic flux, \(\Phi\), through the circuit. All authors have read and agreed to the published version of the manuscript. Energy is stored in a magnetic field. Lets try to interpret each one of these terms in this equation. The Lorentz force is velocity dependent, so cannot be just the gradient of some potential. Accessibility StatementFor more information contact us atinfo@libretexts.orgor check out our status page at https://status.libretexts.org. In ideal magnetohydrodynamics (MHD) the magnetic pressure force in an electrically conducting fluid with a bulk plasma velocity field Along the z-direction, which we assume the magnetic field is applied, (10) E = B 0 by substitution, (11) E = m B 0 The magnitude of the splitting therefore depends on the size of the magnetic field. {\displaystyle \rho } Magnetic Field Created By A Solenoid: Magnetic field created by a solenoid (cross-sectional view) described using field lines. Consequently, a portion of the electrical energy supplied by the electric source is stored as current, is dissipation from the magnetizing coil as heat. So, in order to have a similar type of expression here, lets multiply both numerator by 0 and divide it by 0. Now omitting the explicit dependence on \({\bf r}\) in the integrand for clarity: \[W = q \int_{\mathcal C} \left[ {\bf v} \times {\bf B} \right] \cdot d{\bf l} \label{m0059_eWqint} \]. And again, you can recall the electrical energy density, which is energy per unit volume for a capacitor, and that was equal to uE is equal to, was equal to one-half 0 times square of the electric field. 2022, 27, 58. Legal. Flux density dependency on the nature of the magnetic coupling material of Energy in Electric and Magnetic Fields Both electric fieldsand magnetic fieldsstore energy. This voltage exists even though the force required for movement must be the same on both endpoints, or could even be zero, and therefore cannot be attributed to mechanical forces. The energy density stored in a magnetostatic field established in a linear isotropic material is given by, \[\text{W}_{\text{B}}=\frac{\mu}{2} \text{H}^{2}=\frac{\vec{\text{H}} \cdot \vec{\text{B}}}{2} \quad \text { Joules } / \text{m}^{3}. Proceed by integrating Equation (\ref{5.42}) over all space, then use Gauss theorem to transform the left hand side into a surface integral. https://www.mdpi.com/openaccess. E I = 1 2 v I 2 = 1 2 v F 2 = E F For us to say that the magnetic field did work on the particle we would need to have a change in the energy of the magnetic field, and a corresponding change in the energy of the particle. For more information, please refer to At this point, it is convenient to introduce the electric potential difference \(V_{21}\) between the start point (1) and end point (2) of \({\mathcal C}\). Example 1: Electric field of a point charge, Example 2: Electric field of a uniformly charged spherical shell, Example 3: Electric field of a uniformly charged soild sphere, Example 4: Electric field of an infinite, uniformly charged straight rod, Example 5: Electric Field of an infinite sheet of charge, Example 6: Electric field of a non-uniform charge distribution, Example 1: Electric field of a concentric solid spherical and conducting spherical shell charge distribution, Example 2: Electric field of an infinite conducting sheet charge. Okay, since the total magnetic energy stored in the magnetic field of an inductor is equal to one-half L, inductance, times the square of the current flowing through the inductor and for a solenoid inductance was equal to 0n2 times l times A and n2 was the number density of the turns as you recall and, again, l is the length. is the vacuum permeability and Maxwell's equations predict that regardless of wavelength and frequency, every light wave has the same structure. If it pumping q coulombs of charge through the volts of potential difference, then it makes times q of work done on q by the seat of EMF. P and D.H.; visualization, C.K.T. Therefore, this scenario has limited application in practice. progress in the field that systematically reviews the most exciting advances in scientific literature. {\displaystyle B} To do this, we may sum contributions from points along the path traced out by the particle, i.e., \[W \approx \sum_{n=1}^N \Delta W ({\bf r}_n) \nonumber \], where \({\bf r}_n\) are positions defining the path. \label{5.41}\], This expression for the total energy, UB, can be transformed into an integral over the sources of the magnetostatic field. Eng. where I is the current through the wire; the current must be the same, of course, at all points along the circuit. In our specific case this is going to be equal to UB divided by cross-sectional area of the solenoid times its length, which will give us the volume of that solenoid, a volume through which the magnetic field will fill when certain current i is flowing through the solenoid. As you recall, electromotive force is nothing but a charge pump. B The above formula Magnetic fields are generated by moving charges or by changing electric fields. Heres the equation of magnetic force: Magnetic force acting on a moving charge, F = q v B sin Magnetic force acting on a current carrying wire, F = I L B sin Where, I = electric current, A L = length of a wire, m Lets solve some problems based on these equations, so youll get a clear idea. Magnetic pressure can also be used to propel projectiles; this is the operating principle of a railgun. = {\displaystyle \mu _{0}\mathbf {J} =\nabla \times \mathbf {B} } A changing magnetic field induces an electromotive force (emf) and, hence, an electric field. Toluwaloju, T.; Thein, C.K. OpenStax College, College Physics. , and the vector identity, where the first term on the right hand side is the magnetic tension and the second term is the magnetic pressure force.[1][2]. The magnetic field both inside and outside the coaxial cable is determined by Ampres law. Therefore we conclude that rest of the power is going to go the inductor. 1996-2022 MDPI (Basel, Switzerland) unless otherwise stated. Lets say it has a circular cross section something like this, has the length of l and then the cross-sectional area of A, and we have its associated turns, something like this. For a wire of negligible thickness, \[\int \int \int_{Space} \text{d} \tau\left(\vec{\text{J}}_{f} \cdot \vec{\text{A}}\right) \rightarrow \text{I} \oint_{C} \vec{\text{A}} \cdot \text{d} \vec{\text{L}}, \label{5.45}\]. Presented at the 9th International Electronic Conference on Sensors and Applications, 115 November 2022; Available online: (This article belongs to the Proceedings of, The current revolution in the field of electromagnetic vibration energy harvester requires that both wireless sensor nodes and relevant power sources be cost- and size-optimized while ensuring that, during design/fabrication of the sensors power sources, the power deliverable to the sensors be maximum. (c) Obtain the equations of Equation \ref{m0059_eVAB} is electrical potential induced by charge traversing a magnetic field. , and plasma pressure Energy stored in a magnetic field of self-inductance L and carrying a current of I amperes joules Energy stored in magnetic field joules Now since the magnetising force and al=volume of the magnetic field in m 3 Energy stored/m 3 joules joules in a medium joule in air Magnetic hysteresis and Magnetostriction EFFECTS OF SELF INDUCTION A DC CIRCUIT The following example demonstrates a practical application of this idea. 78. Let the exciting coil is devoid of any resistance (pure, lossless). Analyze the motion of a particle (charge , mass ) in the magnetic field of a long straight wire carrying a steady current . In SI units, the magnetic pressure Here, lets go ahead and multiply both sides of this equation by current i. From the forgone discussions and analysis, the following conclusions were reached: Since the flux is measured in the region where the coil is positioned, we recommend that the inertial mass of the transducer should be concentrated in the coil to allow for resonant variation with little divergence from predicted values. The magnetic field both inside and outside the coaxial cable is determined by Ampres law. So, the magnetic energy of an inductor will be equal to one-half L times inductance times square of the current flowing through that inductor. So in other words, electromotive force is supplying times i of energy in every second to the circuit. This voltage exists even though the wire is perfectly-conducting, and therefore cannot be attributed to the electric field. ; investigation, T.T. So, we can express the energy density in explicit form. Help us to further improve by taking part in this short 5 minute survey, Continuous Rapid Accurate Measurement of the Output Frequency of Ultrasonic Oscillating Temperature Sensors, Recreating Lunar Environments by Fusion of Multimodal Data Using Machine Learning Models, The 9th International Electronic Conference on Sensors and Applications, https://creativecommons.org/licenses/by/4.0/. ; validation, T.T. The transformation can be carried out by means of the vector identity, \[\operatorname{div}(\vec{\text{A}} \times \vec{\text{H}})=\vec{\text{H}} \cdot(\vec{\nabla} \times \vec{\text{A}})-\vec{\text{A}} \cdot(\vec{\nabla} \times \vec{\text{H}}). Equation ( 946) can be rewritten (949) where is the volume of the solenoid. And integral of i di is going to give us i2 over 2. ; resources, C.K.T. Energy is required to establish a magnetic field. March 1, 2013. Now, the second term over here, therefore i is the power supplied, and the first term actually on the right-hand side, i2R, is something we are already familiar, and this is rate at which energy appears as thermal energy in the resistor. T = 2 m q B. p The focus in this work will be to optimize the ironmagnetcoil geometry with the view to realize more compact, lightweight and cost-effective ironmagnetcoil designs. Course Hero is not sponsored or endorsed by any college or university. Please let us know what you think of our products and services. Well, lets denote energy density with small uB, and that is by definition total energy of the inductor divided by total volume of the inductor. The above prediction and approaches shall be verified in a future experimental approach that shall be used to test performances of prototypes. The motion described by \({\bf v}\) may be due to the presence of an electric field, or it may simply be that that charge is contained within a structure that is itself in motion. {\displaystyle \mathbf {B} } \(V_{21}\) is defined as the work done by traversing \({\mathcal C}\), per unit of charge; i.e., \[V_{21} \triangleq \frac{W}{q} \nonumber \]. In physics, magnetic pressure is an energy density associated with a magnetic field. This requires the two terms on the right hand side of (\ref{5.43}) to be equal, and this result can be used to rewrite the expression (\ref{5.41}) in terms of the vector potential and the source current density: \[\text{U}_{\text{B}}=\frac{1}{2} \int \int \int_{S p a c e} \text{d} \tau(\vec{\text{H}} \cdot \vec{\text{B}})=\frac{1}{2} \int \int \int_{S p a c e} \text{d} \tau\left(\vec{\text{J}}_{f} \cdot \vec{\text{A}}\right) . Regarding electromagnetic waves, both magnetic and electric field are equally involved in contributing to energy density. B Editors select a small number of articles recently published in the journal that they believe will be particularly Now, we have created a closed loop using perfectly-conducting and motionless wire to form three sides of a rectangle, and assigned the origin to the lower left corner. So, the energy density will therefore be equal to B2 over 2 times permeability of free space, and that expression gives us the magnetic energy density. With the substitution of Equation The incremental work \(\Delta W\) done by moving the particle a short distance \(\Delta l\), over which we assume the change in \({\bf F}_m\) is negligible, is, \[\Delta W \approx {\bf F}_m\cdot\hat{\bf l}\Delta l \label{m0059_WeFdl} \]. See further details. , mass density This energy can be found by integrating the magnetic energy density, u m = B 2 2 0. over the appropriate volume. A magnetic field is a mathematical description of the magnetic influences of electric currents and magnetic materials. It was due to the fact that as we cross a resistor in the direction of flow of current, the potential decreases by i times R. And during the rise of current as the current builds up from 0 to i were going to end up with a self-induced EMF, and that will show up such that it will oppose its cause. Disclaimer/Publishers Note: The statements, opinions and data contained in all publications are solely Therefore A times l is going to represent the volume of the solenoid. This equivalence can be seen by using the definition \(\vec B\) = curl(\(\vec A\)) along with Stokes theorem to transform the integral for the flux: \[\Phi=\int \int_{S} \vec{\text{B}} \cdot \text{d} \vec{\text{S}}=\int \int_{S} \operatorname{curl}(\vec{\text{A}}) \cdot \text{d} \vec{\text{S}}=\oint_{C} \vec{\text{A}} \cdot \text{d} \vec{\text{L}} , \label{5.46}\], where the curve C bounds the surface S. Combining Equations (\ref{5.46}) and (\ref{5.44}), the magnetic energy associated with a single circuit can be written, \[\text{U}_{\text{B}}=\frac{1}{2} \int \int \int_{S p a c e} \text{d} \tau\left(\vec{\text{J}}_{f} \cdot \vec{\text{A}}\right)=\frac{1}{2} \text{I} \Phi , \label{5.47}\], \[\text{U}_{\text{B}}=\frac{1}{2} \sum_{k=1}^{N} \text{I}_{\text{k}} \Phi_{k} . {\displaystyle P_{B}} {\displaystyle \mu _{0}} \label{5.42}\], (There is a nice discussion of this identity in The Feynman Lectures on Physics, Vol.II, section 27.3, by R.P.Feynman, R.B.Leighton, and M.Sands, Addison-Wesley, Reading, Mass.,1964). That is also equivalent, therefore, power supplied. Thus, management of magnetic pressure is a significant challenge in the design of ultrastrong electromagnets. Y is 0 for high frequency currents carried mostly by the outer surface of the conductor, and 0.25 for DC currents distributed evenly throughout the conductor. Example 2: Potential of an electric dipole, Example 3: Potential of a ring charge distribution, Example 4: Potential of a disc charge distribution, 4.3 Calculating potential from electric field, 4.4 Calculating electric field from potential, Example 1: Calculating electric field of a disc charge from its potential, Example 2: Calculating electric field of a ring charge from its potential, 4.5 Potential Energy of System of Point Charges, 5.03 Procedure for calculating capacitance, Demonstration: Energy Stored in a Capacitor, Chapter 06: Electric Current and Resistance, 6.06 Calculating Resistance from Resistivity, 6.08 Temperature Dependence of Resistivity, 6.11 Connection of Resistances: Series and Parallel, Example: Connection of Resistances: Series and Parallel, 6.13 Potential difference between two points in a circuit, Example: Magnetic field of a current loop, Example: Magnetic field of an infinitine, straight current carrying wire, Example: Infinite, straight current carrying wire, Example: Magnetic field of a coaxial cable, Example: Magnetic field of a perfect solenoid, Example: Magnetic field profile of a cylindrical wire, 8.2 Motion of a charged particle in an external magnetic field, 8.3 Current carrying wire in an external magnetic field, 9.1 Magnetic Flux, Fradays Law and Lenz Law, 9.9 Energy Stored in Magnetic Field and Energy Density, 9.12 Maxwells Equations, Differential Form. Instead, the reverse is true: i.e., it is the motion of the particle that is giving rise to the force. So, were considering a solenoid. This paper presents on the realization of an approach to ensure an accurate prediction of size-optimized but maximum power output on the electromagnetic transducer of a VEH. permission is required to reuse all or part of the article published by MDPI, including figures and tables. The authors declare no conflict of interest. This gradient in field strength gives rise to a magnetic pressure force that tends to stretch the wire uniformly outward. A gradient in field strength causes a force due to the magnetic pressure gradient called the magnetic pressure force. Magnetic energy and electrostatic potential energy are related by Maxwell's equations. We also acknowledge previous National Science Foundation support under grant numbers 1246120, 1525057, and 1413739. r = m v q B. and D.H.; writingoriginal draft preparation, T.T. The strength of the force is related to the electric constant . We can take it outside of the integral. where It is identical to any other physical pressure except that it is carried by the magnetic field rather than (in the case of a gas) by the kinetic energy of gas molecules. So we can say then Li di over dt is nothing but equal dUB over dt, which is the rate of magnetic stored in the magnetic field of the inductor, or it is rate at which energy stored in the magnetic field of the inductor. Thus, we see that endpoint 2 is at an electrical potential of \(Bvl\) greater than that of endpoint 1. No magnetic monopoles are known to exist. This type of methods, instructions or products referred to in the content. The formula for the energy stored in a magnetic field is E = 1/2 LI 2. Particle in a Magnetic Field. Proc. WB = 2H2 = H B 2 Joules / m3. Using Equation (7), we reformulate Equation (3) to an equation as shown in Equation (8). In the eventuality of using more than one magnet, Equation (4) sets an order for which the transduction magnet must be aligned to allow for continuous flux linkage between the several magnets in such a manner that no pole is isolated. To describe the energy of a magnetic field (coil), a formula for magnetic energy can be set up. The canonical momentum pi is defined by the equation pi = L qi and the Hamiltonian is defined by performing a Legendre transformation of the Lagrangian: H(qi, pi) = i (piqi L(qi, qi)) It is straightforward to check that the equations of motion can be written: qi = H pi, pi = H qi These are known as Hamiltons Equations. Summary. The current revolution in the field of electromagnetic vibration energy harvester requires that both wireless sensor nodes and relevant power sources be cost- and size-optimized while ensuring that, during design/fabrication of the sensors power sources, the power deliverable to the sensors be maximum. (a) Is its kinetic energy conserved? 0 In this circuit, if we consider the rise of current phase, we have a resistor and an inductor connected in series, and once we turn the switch in on position, current i will emerge from the power supply, run through resistor R and through an inductor with an inductance of L from positive terminal towards the negative terminal of the power supply. magnetic field strength, also called magnetic intensity or magnetic field intensity, the part of the magnetic field in a material that arises from an external current and is not intrinsic to the material itself. It is expressed as the vector H and is measured in units of amperes per metre. The definition of H is H = B/ M, where B is the magnetic flux density, a measure of the actual ; Halim, D. An Effect of Coupling Factor on the Power Output for Electromagnetic Vibration Energy Harvester. If E = 1/2 is the formula for storing energy in a magnetic field, this energy is stored in the form of a magnetic field. {\displaystyle p} In other words, that is nothing but power dissipated through the resistor. ; project administration, C.K.T. learning objectives Describe the relationship between the changing magnetic field and an electric field We have studied Faradays law of induction in previous atoms. According to the law, the equation gives the magnetic field at a distance r from The magnetic field at any given point is specified by both a direction and a magnitude. {\displaystyle B} Now, we are able to determine the change in potential energy for a charged particle moving along any path in space, given the magnetic field. Thus, \[\begin{align} {\bf v} \times {\bf B} &= \hat{\bf z}v \times \hat{\bf x}B \nonumber \\ &= \hat{\bf y} B v\end{align} \nonumber \], Taking endpoints 1 and 2 of the wire to be at \(y=y_0\) and \(y=y_0+l\), respectively, we obtain, \[\begin{align} V_{21} &= \int_{y_0}^{y_0+l} \left[ \hat{\bf y} B v \right] \cdot \hat{\bf y}dy \nonumber \\ &= Bvl\end{align} \nonumber \]. In SI units, the energy density If the coil current when zero at t=0 and has attained the value of I amperes at t=T, the energy input to the coil during this interval of T second is. Papers are submitted upon individual invitation or recommendation by the scientific editors and undergo peer review ; Park, J.Y. Conceptualization, C.K.T. When a coil is connected to an electric source, the current flowing in the circuit gradually increases from zero to its final value, and a magnetic field is established. Now let us try to generalize this result. The total energy stored in the magnetostatic field is obtained by integrating the energy density, WB, over all space (the element of volume is d\(\tau\)): \[\text{U}_{\text{B}}=\int \int \int_{S p a c e} \text{d} \tau\left(\frac{\vec{\text{H}} \cdot \vec{\text{B}}}{2}\right). {\displaystyle P_{B}} 9.9 Energy Stored in magnetic field and energy density. \label{5.48}\]. Solution: Given, E = 5V/m. To do that, lets consider a solenoid and lets assume that l represents the length of the solenoid and A represents the cross-sectional area of the solenoid. Here, a straight perfectly-conducting wire of length \(l\) is parallel to the \(y\) axis and moves at speed \(v\) in the \(+z\) direction through a magnetic field \({\bf B}=\hat{\bf x}B\). Only the shorting bar is in motion, so \({\bf v}=0\) for the other three sides of the loop. We will end up with energy density of a solenoid being equal to one-half 0n2 times i2. The unit of magnetic energy density at any point of a magnetic field in vacuum is (total energy: E) the following units and sizes are needed: (magnetic field strength, CGS system: Oersted unit) Summary. The physical meaning of Equations (4) and (5) asserts that, for any magnetic system/magnet, there are no isolated magnetic poles, and circulating magnetic fields are produced by changing electric currents. {\displaystyle \mathbf {v} } prior to publication. Multiplying both sides of above equation by I, we have the power input to the coil, Which is positive when both and di/dt have the same sign, else it is negative. You are accessing a machine-readable page. If the magnetic flux does not change with time, then there will be no current. The dimensional formula of a magnetic field is equal to M 1 T -2 I -1. The dimensional formula of a magnetic field can be defined as the representation of units of a magnetic field in terms of fundamental physical quantities with appropriate power. The dimensional formula of Magnetic field is given as M 1 T -2 I -1. Interplay between magnetic pressure and ordinary gas pressure is important to magnetohydrodynamics and plasma physics. , current density The significance of the combined effects of electric and magnetic fields is useful where one can create a strong Lorentz force for industry applications. A magnetic field (MF), which can be thought of as a vector field, governs the magnetic effect on stirring rechargeable tasks, power-driven flows, and magnetic resources. (9) E = B 0 where B 0 is the external magnetic field. \label{5.40}\]. Figure 1 depicts an iron-cored coil when the resistance of the resistance of the coil lumped outside so that the exciting coil is devoid of any resistance (pure, lossless). In other words, the same potential \(V_T\) would exist even if the gap was not closed by a resistor. Example 5: Electric field of a finite length rod along its bisector. and D.H.; formal analysis, T.T. is. This potential gives rise to a current \(Bvl/R\), which flows in the counter-clockwise direction. The latter expression is similar to Equation (3.3.6) for the electrostatic energy associated with a collection of charged conductors: currents in the magnetostatic case play a role similar to that of charges in the electrostatic case, and flux plays a role that is similar to the role played by the potentials. The energy of a capacitor is stored in the electric field between its plates. Please note that many of the page functionalities won't work as expected without javascript enabled. Engineering Proceedings. Toluwaloju, T.I. Using the formula for magnetic field we have, B = o IN/L. P To accomplish something useful with this concept we must at least form a closed loop, so that current may flow. In physics, magnetic pressure is an energy density associated with a magnetic field.In SI Answer: The magnitude of the electric current can be calculated by rearranging the magnetic field formula: The magnitude of the magnetic field is given in nano-Tesla. The prefix "nano" means 10 -9, and so . 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